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Proof step 25 from proof refine-change (
previous step
)
⊦ q1.lebrefs ⊆ q0.lebrefs ++ (v × m) ∧ abs(avols, apebs, vols, q0) ∧ v ∈ avols ∧ m < # avols[v] ∧ avols[v][m] ≠ erased → abs(avols, apebs, vols, q1)
A spec-lemma