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Proof step 14 from proof refine-create-volume (previous step)

# apebs0 = # wlar0, # apebs = # wlar, abs(avols, apebs, vols, q), bflipset-cons(bflipset0, wlar0), bflipset-cons(bflipset, wlar), ebm-cons(avols), id(apebs0, apebs, mapped-pebs(vols0)), ubi-io-inv(apebs0), ubi-io-inv(apebs), unique-sqns(apebs0), unique-sqns(apebs), valid-ebatbl(apebs0, wlar0, vols0, vtblpnum0), valid-ebatbl(apebs, wlar, vols, vtblpnum), valid-eraseq(q0), valid-eraseq(wlar0, q0), valid-eraseq(apebs0, q0), valid-eraseq(q), valid-eraseq(wlar, q), valid-eraseq(apebs, q), valid-global-sqn(apebs0, sqnum0), valid-global-sqn(apebs, sqnum), valid-vtbl(apebs0, vols0, wlar0, vtblpnum0), valid-vtbl(apebs, vols, wlar, vtblpnum), valid-wl(apebs0, wlar0), valid-wl(apebs, wlar), err1 = ESUCCESS → ¬ v ∈ vols ∧ vols0 = vols[v, fill(mkebatbl(n), unmapped)] ∧ q0.lebrefs ⊆ ∅ ++ (VTBL_VOLID × VTBL_LNUM), err1 ≠ ESUCCESS → q0.lebrefs ⊆ q.lebrefs ∧ vols0 = vols, err1 = ESUCCESS ∨ ⌊err1⌋ ⊦ ⟨err := err1; if err = ESUCCESS then avols[v] := fill(mkabstractvolume(n), erased)⟩ (abs(avols, apebs0, vols0, q0) ∧ err1 = err), VTBL_VOLID ∈ vols0, VTBL_VOLID ∈ vols, v ∈ avols

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Rule argument

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