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Proof step 6 from proof refine-erase-worker (previous step)

# apebs = # wlar, eqent = q.head, abs(avols, apebs, vols, q), bflipset-cons(bflipset, wlar), ebm-cons(avols), ubi-io-inv(apebs), unique-sqns(apebs), valid-ebatbl(apebs, wlar, vols, vtblpnum), valid-eraseq(apebs, q), valid-eraseq(wlar, q), valid-eraseq(q), valid-global-sqn(apebs, sqnum), valid-vtbl(apebs, vols, wlar, vtblpnum), valid-wl(apebs, wlar) ⊦ ⟪ubi_erase_worker_helper#(eqent.pnum; wlar, apebs; err); if err = ESUCCESS then q := q.tail⟫ ⟨skip⟩ abs(avols, apebs, vols, q), q = [], VTBL_VOLID ∈ vols

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
# apebs = # wlar, q ≠ [], abs(avols, apebs, vols, q), bflipset-cons(bflipset, wlar), ebm-cons(avols), ubi-io-inv(apebs), unique-sqns(apebs), valid-ebatbl(apebs, wlar, vols, vtblpnum), valid-eraseq(q), valid-eraseq(wlar, q), valid-eraseq(apebs, q), valid-global-sqn(apebs, sqnum), valid-vtbl(apebs, vols, wlar, vtblpnum), valid-wl(apebs, wlar), ¬ VTBL_VOLID ∈ vols ⊦ ⟪ubi_erase_worker_helper#(q.head.pnum; wlar, apebs; err); if err = ESUCCESS then q := q.tail⟫ ⟨skip⟩ abs(avols, apebs, vols, q)

Proof step 6 from proof refine-erase-worker (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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