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Proof step 19 from proof refine-erase (previous step)

# apebs = # wlar0, vols[v][vtblpnum2] = ⌜n⌝ , lref = v × vtblpnum2, vtblpnum = vols[v][vtblpnum2].pnum, wlar = wlar0[vtblpnum, wlar0[vtblpnum].status:= erasing], avols[v][vtblpnum2].mapped?, vtblpnum2 < # vols[v], vtblpnum2 < # avols[v], n < # wlar0, vtblpnum < # wlar0, abs(avols, apebs, vols, q), bflipset-cons(bflipset, wlar0), ebm-cons(avols), ubi-io-inv(apebs), unique-sqns(apebs), valid-ebatbl(apebs, wlar0, vols, vtblpnum1), valid-eraseq(q), valid-eraseq(wlar0, q), valid-eraseq(apebs, q), valid-global-sqn(apebs, sqnum), valid-vtbl(apebs, vols, wlar0, vtblpnum1), valid-wl(apebs, wlar0), v ∈ vols, v ∈ avols ⊦ [q := q + eq-entry(vtblpnum, lref)] ( # apebs = # wlar ∧ valid-wl(apebs, wlar) ∧ valid-eraseq(q) ∧ valid-eraseq(wlar, q) ∧ valid-eraseq(apebs, q) ∧ ¬ VTBL_VOLID ∈ vols[v, vols[v][vtblpnum2, unmapped]] ∧ bflipset-cons(bflipset -- vols[v][vtblpnum2].pnum, wlar) ∧ valid-ebatbl(apebs, wlar, vols[v, vols[v][vtblpnum2, unmapped]], vtblpnum1) ∧ valid-vtbl(apebs, vols, wlar, vtblpnum1) → ⟪ubi_erase_all#(vols[v, vols[v][vtblpnum2, unmapped]], bflipset -- vols[v][vtblpnum2].pnum, vtblpnum1, sqnum; wlar, q, apebs; err)⟫ ⟨ebm_erase#(v, vtblpnum2; avols; err0)⟩ (abs(avols, apebs, vols[v, vols[v][vtblpnum2, unmapped]], q) ∧ err = err0)), vols[v][vtblpnum2] = unmapped, VTBL_VOLID ∈ vols

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Rule argument

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