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Proof step 5 from proof refine-get-volume-size (previous step)

# apebs = # wlar, abs(avols, apebs, vols, q), bflipset-cons(bflipset, wlar), ebm-cons(avols), ubi-io-inv(apebs), unique-sqns(apebs), valid-ebatbl(apebs, wlar, vols, vtblpnum), valid-eraseq(q), valid-eraseq(wlar, q), valid-eraseq(apebs, q), valid-global-sqn(apebs, sqnum), valid-vtbl(apebs, vols, wlar, vtblpnum), valid-wl(apebs, wlar), v ∈ avols ⊦ ⟪n := # vols[v]⟫ ⟨ebm_get_volume_size#(v, avols; ; n0)⟩ (n = n0), VTBL_VOLID ∈ vols

Heuristic symbolic execution applied rule assign right

And obtained the following new goals

Proof step 6:
# apebs = # wlar, abs(avols, apebs, vols, q), bflipset-cons(bflipset, wlar), ebm-cons(avols), ubi-io-inv(apebs), unique-sqns(apebs), valid-ebatbl(apebs, wlar, vols, vtblpnum), valid-eraseq(apebs, q), valid-eraseq(wlar, q), valid-eraseq(q), valid-global-sqn(apebs, sqnum), valid-vtbl(apebs, vols, wlar, vtblpnum), valid-wl(apebs, wlar), v ∈ vols, v ∈ avols ⊦ ⟨ebm_get_volume_size#(v, avols; ; n0)⟩ (# vols[v] = n0), VTBL_VOLID ∈ vols

Rule argument

Additional information

Used simplifier rules: ⊦ v ∈ avols ∧ abs(avols, apebs, vols, q) → v ∈ vols; (ss)