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Proof step 103 from proof refine-read (previous step)

# vols[v] = # avols[v], # apebs = # wlar, apebs[n1] = mkpeb(aehdr, avhdr, buf1, m, false), vols[v][vtblpnum5] = ⌜n1⌝ , avols[v][vtblpnum5] = mapped(buf1, m0), vtblpnum5 < # avols[v], n1 < # wlar, bflipset-cons(bflipset, wlar), ebm-cons(avols), ubi-io-inv(apebs), ubi-io-peb-inv(mkpeb(aehdr, avhdr, buf1, m, false)), unique-sqns(apebs), valid-ebatbl(apebs, wlar, vols, vtblpnum3), valid-eraseq(apebs, q), valid-eraseq(wlar, q), valid-eraseq(q), valid-global-sqn(apebs, sqnum), valid-vtbl(apebs, vols, wlar, vtblpnum3), valid-wl(apebs, wlar), v ∈ vols, v ∈ avols, m ≤ m0, n0 + n ≤ # buf2, vtblpnum4 + n ≤ LEB_SIZE, ⌊err0⌋ ⊦ VTBL_VOLID ∈ vols, ∃ buf1. # buf1 = # buf2 ∧ range=(buf1, 0, buf2, 0, n0) ∧ range=(buf1, n0 + n, buf2, n0 + n, # buf2 - n0 + n)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 104:
# apebs = # wlar, # vols[v] = # avols[v], # buf2 = n2 + n0 + n, avols[v][vtblpnum5] = mapped(buf1, m0), vols[v][vtblpnum5] = ⌜n1⌝ , apebs[n1] = mkpeb(aehdr, avhdr, buf1, m, false), n1 < # wlar, vtblpnum5 < # avols[v], bflipset-cons(bflipset, wlar), ebm-cons(avols), ubi-io-inv(apebs), ubi-io-peb-inv(mkpeb(aehdr, avhdr, buf1, m, false)), unique-sqns(apebs), valid-ebatbl(apebs, wlar, vols, vtblpnum3), valid-eraseq(q), valid-eraseq(wlar, q), valid-eraseq(apebs, q), valid-global-sqn(apebs, sqnum), valid-vtbl(apebs, vols, wlar, vtblpnum3), valid-wl(apebs, wlar), v ∈ avols, v ∈ vols, vtblpnum4 + n ≤ LEB_SIZE, n0 + n ≤ # buf2, m ≤ m0, ⌊err0⌋ ⊦ VTBL_VOLID ∈ vols, ∃ buf1. # buf1 = # buf2 ∧ range=(buf1, 0, buf2, 0, n0) ∧ range=(buf1, n0 + n, buf2, n0 + n, n2)

Rule argument

spec: nat name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [n, m, n0] → [n0 + n, # buf2, n2]

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: n0 + n, # buf2, n2