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Proof step 120 from proof refine-read (previous step)

# vols[v] = # avols[v], # apebs = # wlar, apebs[n1] = mkpeb(aehdr, avidhdr(v, m1, m2, m3, m4), buf1, m, true), vols[v][m1] = ⌜n1⌝ , avols[v][m1] = mapped(buf1, m0), wlar[n1] = wl-entry(m5, used), m1 < # avols[v], n1 < # wlar, bflipset-cons(bflipset, wlar), ebm-cons(avols), ubi-io-inv(apebs), ubi-io-peb-inv(mkpeb(aehdr, avidhdr(v, m1, m2, m3, m4), buf1, m, true)), unique-sqns(apebs), valid-eraseq(apebs, q), valid-eraseq(wlar, q), valid-eraseq(q), valid-global-sqn(apebs, sqnum), valid-vtbl(apebs, vols, wlar, vtblpnum3), v ∈ vols, v ∈ avols, m ≤ m0, n0 + n ≤ # buf2, vtblpnum4 + n ≤ LEB_SIZE, ∀ n. n < # wlar → (wlar[n].status = erroneous ↔ apebs[n].bad) ∧ (wlar[n].status = free → apebs[n].vidhdr = empty) ∧ (wlar[n].status ≠ erroneous ∧ wlar[n].status ≠ erasing → apebs[n].echdr = aechdr(wlar[n].ec)) ∧ (wlar[n].status = used → (∃ v, m. valid-peb(v, m, apebs[n]) ∧ apebs[n].vidhdr.sqn = valid-sqns(v, m, apebs).max)) ⊦ n1 = vtblpnum3, VTBL_VOLID ∈ vols

User applied rule all left

And closed the goal!

Rule argument

pos: left 24 terms: n1 abort: F discard: T computed: T

Additional information

Used simplifier rules: ⊦ wl-entry(m, stat).status = stat; (s)% ⊦ used ≠ erroneous; (s)% ⊦ mkpeb(aehdr, avhdr, buf, m, boolvar).bad ↔ boolvar; (s) Used terms: n1