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Proof step 23 from proof refine-unmap (previous step)

# apebs = # wlar, unmapped = vols[v][vtblpnum], vtblpnum < # vols[v], vtblpnum < # avols[v], abs(avols, apebs, vols, q), bflipset-cons(bflipset, wlar), ebm-cons(avols), ubi-io-inv(apebs), unique-sqns(apebs), valid-ebatbl(apebs, wlar, vols, vtblpnum1), valid-eraseq(q), valid-eraseq(wlar, q), valid-eraseq(apebs, q), valid-global-sqn(apebs, sqnum), valid-vtbl(apebs, vols, wlar, vtblpnum1), valid-wl(apebs, wlar), v ∈ vols, v ∈ avols ⊦ ⟨avols[v][vtblpnum] := unmapped⟩ abs(avols, apebs, vols, q), avols[v][vtblpnum].mapped?, VTBL_VOLID ∈ vols

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ v ∈ vols ∧ m < # vols[v] ∧ abs(avols, apebs, vols, q) → m < # avols[v]; (ss)% ⊦ v ∈ vols ∧ abs(avols, apebs, vols, q) → v ∈ avols; (ss)%⊦ v ∈ vols ∧ m < # vols[v] ∧ vols[v][m] = unmapped ∧ abs(avols, apebs, vols, q) → abs(avols[v, avols[v][m, unmapped]], apebs, vols, q); (ss)