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Proof step 5 from proof subarray-add-eq-mkempbuf (previous step)

# subarray(buf, m, n0 + n1) = # mkempbuf(n), m + n0 + n1 ≤ # buf, ∀ n2. n2 < # subarray(buf, m, n0 + n1) → subarray(buf, m, n0 + n1)[n2] = mkempbuf(n)[n2] ⊦ subarray(buf, m, n0) = mkempbuf(n0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
m + n0 + n1 ≤ # buf, ∀ n. n < n0 + n1 → buf[m + n] = empty ⊦ subarray(buf, m, n0) = mkempbuf(n0)

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → mkempbuf(n)[m] = empty; (s)% ⊦ n0 < n → subarray(buf, m, n)[n0] = buf[m + n0]; (s)% ⊦ # mkempbuf(n) = n; (s)% ⊦ # subarray(buf, m, n) = n; (s)