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Proof step 2 from proof valid-peb-imp-valid-peb0 (previous step)

valid-peb(v, m, apeb) ⊦ valid-peb(apeb)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
apeb.vidhdr = avidhdr(v, m, m0, m1, m2), apeb.echdr.valid?, m1 ≠ 0 → m1 ≤ datasize(apeb.data) ∧ m2 = checksum(apeb.data, m1) ⊦ apeb.bad, ∃ v0, m3, m0, m1, m2. apeb.vidhdr = avidhdr(v0, m3, m0, m1, m2) ∧ (m1 ≠ 0 → m1 ≤ datasize(apeb.data) ∧ m2 = checksum(apeb.data, m1))

Rule argument

Additional information

Used simplifier rules: valid-peb2: ⊦ valid-peb(v, m, apeb) ↔ ¬ apeb.bad ∧ apeb.echdr.valid? ∧ (∃ m0, m1, m2. apeb.vidhdr = avidhdr(v, m, m0, m1, m2) ∧ ( m1 ≠ 0 → m1 ≤ datasize(apeb.data) ∧ m2 = checksum(apeb.data, m1)));%valid-peb0: ⊦ valid-peb(apeb) ↔ (∃ v, m. valid-peb(v, m, apeb));