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Proof step 11 from proof to-vtbl-at (previous step)

v ∈ vols0[v0, ebatbl], ∀ vols1, v. # vols1 < # vols0[v0, ebatbl] → v ∈ vols1 → to-vtbl(vols1)[v] = # vols1[v] ⊦ to-vtbl(vols0)[v0, # ebatbl][v] = # vols0[v0, ebatbl][v], v0 ∈ vols0

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 12:
v ∈ vols0[v0, ebatbl], ∀ vols1, v. # vols1 < # vols0[v0, ebatbl] → v ∈ vols1 → to-vtbl(vols1)[v] = # vols1[v] ⊦ to-vtbl(vols0)[v0, # ebatbl][v] = # vols0[v0, ebatbl][v], v = v0, v0 ∈ vols0

Rule argument

fma: v = v0

Additional information

Used simplifier rules: ⊦ vtbl[v, n][v] = n; (s)% ⊦ vols[v, ebatbl][v] = ebatbl; (s) Used formulas: v = v0