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Proof step 10 from proof to-vtbl-update (previous step)

v ∈ vols ⊦ to-vtbl(vols -- v)[v0] = to-vtbl(vols)[v0], v0 = v, v0 ∈ vols -- v

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
v ∈ vols ⊦ to-vtbl(vols -- v)[v0] = to-vtbl(vols)[v0], v0 ∈ vols

Rule argument

Additional information

Used simplifier rules: ⊦ v ∈ vols -- v0 ↔ v ≠ v0 ∧ v ∈ vols; (s)