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Proof step 16 from proof in-free-h (previous step)

wlar[m0] = wl-entry(m3, free), wlar[m] = wl-entry(m2, free), m0 < # wlar, m < # wlar, m0 < m, m0 + 1 < # wlar, m3 ∈ free-ecs(wlar, m) ⊦ #(free-ecs(wlar, m) ++ m2) = 0, # free-ecs(wlar, m) = 0, free-ecs(wlar, m) = ∅, ∃ m1. ¬ m < m1 ∧ wlar[m1].status = free ∧ wlar[m1].ec = m3

User applied rule exists right

And closed the goal!

Rule argument

pos: right 4 terms: m0 abort: F discard: T computed: F

Additional information

Used simplifier rules: ⊦ m < n → ¬ n < m; (s)% ⊦ wl-entry(m, stat).status = stat; (s)% ⊦ wl-entry(m, stat).ec = m; (s) Used terms: m0