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Proof step 23 from proof in-free-h (previous step)

m3 ∈ free-ecs(wlar, m) ↔ (∃ m1. m1 < m ∧ wlar[m1].status = free ∧ wlar[m1].ec = m3), wlar[m] = wl-entry(m2, stat), wlar[m0] = wl-entry(m3, stat0), stat0 = free, m0 < # wlar, m < # wlar, m0 ≤ m ⊦ m3 ∈ (stat = free ⊃ free-ecs(wlar, m) ++ m2;free-ecs(wlar, m))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 24:
m3 ∈ free-ecs(wlar, m) ↔ (∃ m1. m1 < m ∧ wlar[m1].status = free ∧ wlar[m1].ec = m3), wlar[m0] = wl-entry(m3, free), wlar[m] = wl-entry(m2, stat), m < # wlar, m0 < # wlar, m0 ≤ m ⊦ m3 ∈ (stat = free ⊃ free-ecs(wlar, m) ++ m2;free-ecs(wlar, m))

Proof step 23 from proof in-free-h (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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