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Proof step 26 from proof in-free-h (previous step)

wlar[m0] = wl-entry(m3, free), wlar[m] = wl-entry(m2, free), m < # wlar, m0 < # wlar, m0 ≤ m ⊦ m3 = m2, m3 ∈ free-ecs(wlar, m), ∃ m1. m1 < m ∧ wlar[m1].status = free ∧ wlar[m1].ec = m3

User applied rule exists right

And closed the goal!

Rule argument

pos: right 3 terms: m0 abort: F discard: F computed: F

Additional information

Used simplifier rules: ⊦ wl-entry(m, stat).status = stat; (s)% ⊦ wl-entry(m, stat).ec = m; (s)% ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m ≤ n → (n ≤ m ↔ m = n); (s)%lf-02: ⊦ m < n ∧ m = n0 → n0 < n; (forward) from specification nat-basic% ⊦ m ≤ m; (s)% ⊦ wl-entry(m, stat) = wl-entry(m0, stat0) ↔ m = m0 ∧ stat = stat0; (ws) Used terms: m0