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Proof step 1 from proof same-used-idexpt (conclusion)

stat ≠ used, stat0 ≠ used ⊦ id○(wlar0, wlar1, m) ∧ wlar0[m] = wl-entry(m0, stat) ∧ wlar1[m] = wl-entry(m1, stat0) → same-used(wlar0, wlar1)

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information