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Proof step 9 from proof same-used2-idexpt (previous step)

# wlar1 = # wlar2, # wlar0 = # wlar2, wlar2[n] = wl-entry(m3, stat2), wlar1[m] = wl-entry(m0, stat), wlar2[m] = wl-entry(m1, stat0), wlar0[n] = wl-entry(m2, stat1), n < # wlar2, n < # wlar2 ∧ n ≠ m → wlar1[n] = wlar2[n], ∀ n. n < # wlar2 → (wlar0[n].status = used ↔ wlar1[n].status = used) ⊦ stat1 = used ↔ stat2 = used, stat = used, stat0 = used

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
# wlar0 = # wlar2, # wlar1 = # wlar2, wlar0[n] = wl-entry(m2, stat1), wlar2[m] = wl-entry(m1, stat0), wlar1[m] = wl-entry(m0, stat), wlar2[n] = wl-entry(m3, stat2), n < # wlar2, n ≠ m → wlar1[n] = wl-entry(m3, stat2), ∀ n. n < # wlar2 → (wlar0[n].status = used ↔ wlar1[n].status = used) ⊦ stat1 = used ↔ stat2 = used, stat = used, stat0 = used

Proof step 9 from proof same-used2-idexpt (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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