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Proof step 15 from proof abs-acyclic (previous step)

ad.meta = tree[p].meta, ad.size = # ad.entries, entries[str] = ROOT_INO, dirs[ino] = mkdir(# entries, md, # links(ino, dirs), m0, entries), (((ino0 => ad * abs(tree[p].entries, ad.entries)) * abs|(tree, ROOT_INO, p, ino0)))(dirs), tree[p].dir?, abs(tree, ROOT_INO)(dirs), afs-cons(dirs, files), fids-cons(tree, abs-files(files), ofh), ispath(p, ROOT_INO, ino, dirs, files), ino ∈ dirs, str ∈ entries ⊦

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 16:
dirs[ino] = mkdir(# entries, md, # links(ino, dirs), m0, entries), entries[str] = ROOT_INO, ad = mkdir(m, md0, m1, m2, entries0), m = # entries0, md0 = tree[p].meta, (((ino0 => ad * abs(tree[p].entries, entries0)) * abs|(tree, ROOT_INO, p, ino0)))(dirs), tree[p].dir?, abs(tree, ROOT_INO)(dirs), afs-cons(dirs, files), fids-cons(tree, abs-files(files), ofh), ispath(p, ROOT_INO, ino, dirs, files), str ∈ entries, ino ∈ dirs ⊦

Rule argument

spec: abstract-dir name: elim seq: ⊦ ( ((m = ad.size ∧ md = ad.meta) ∧ m0 = ad.nlink) ∧ m1 = ad.nsubdirs) ∧ entries = ad.entries ↔ ad = mkdir(m, md, m0, m1, entries) subst: [ad, m, md, m0, m1, entries] → [ad, m, md0, m1, m2, entries0]

Additional information

Used simplifier rules: ⊦ ( ((m = ad.size ∧ md = ad.meta) ∧ m0 = ad.nlink) ∧ m1 = ad.nsubdirs) ∧ entries = ad.entries ↔ ad = mkdir(m, md, m0, m1, entries); (elim) Used terms: ad, m, md0, m1, m2, entries0