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Proof step 2 from proof abs-unfold-entry-p (previous step)

str ∈ entries, entries[str] ∈ dirs0, dirs1 ≡ dirs0[entries[str], ad] ⊦ ((abs(sdt, entries) * D))(dirs0) ↔ str ∈ sdt ∧ ((abs(sdt[str], entries[str]) * abs(sdt -- str, entries -- str) * D))(dirs0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
entries[str] ∈ dirs0, str ∈ entries, dirs1 ≡ dirs0[entries[str], ad] ⊦ ((abs(sdt, entries) * D))(dirs0) ↔ str ∈ sdt ∧ ((abs(sdt[str], entries[str]) * abs(sdt -- str, entries -- str) * D))(dirs0)

Proof step 2 from proof abs-unfold-entry-p (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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