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Proof step 19 from proof abs-unfold (previous step)

tree[p] = dnode(md, sdt), ((abs|(tree, ROOT_INO, p, ino) * ino => mkdir(# entries, md, # links(ino, dirs), m1, entries) * abs(sdt, entries)))(dirs), afs-cons(dirs, files), fids-cons(tree, abs-files(files), ofh), ispath(p, ROOT_INO, ino, dirs, files), p ∈ tree ⊦ abs(tree, ROOT_INO)(dirs), abs(tree0, ROOT_INO)(dirs0)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 20:
⊦ p ∈ tree → abs(tree, ino0) = _∃(λ ino1. abs|(tree, ino0, p, ino1) * abs(tree[p], ino1))
Proof step 21:
tree[p] = dnode(md, sdt), ((abs|(tree, ROOT_INO, p, ino) * ino => mkdir(# entries, md, # links(ino, dirs), m1, entries) * abs(sdt, entries)))(dirs), afs-cons(dirs, files), fids-cons(tree, abs-files(files), ofh), ispath(p, ROOT_INO, ino, dirs, files), p ∈ tree ⊦ (_∃(λ ino1. abs|(tree, ROOT_INO, p, ino1) * abs(tree[p], ino1)))(dirs), abs(tree0, ROOT_INO)(dirs0)

Rule argument

spec: vfs-abs name: path-unfold seq: ⊦ p ∈ tree → abs(tree, ino0) = _∃(λ ino1. abs|(tree, ino0, p, ino1) * abs(tree[p], ino1)) subst: [p, ino0, tree] → [p, ROOT_INO, tree] flags: <all paths>

Additional information

Used terms: p, ROOT_INO, tree