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Proof step 22 from proof abs-unfold (previous step)

tree[p] = dnode(md, sdt), ((abs|(tree, ROOT_INO, p, ino) * ino => mkdir(# entries, md, # links(ino, dirs), m1, entries) * abs(sdt, entries)))(dirs), afs-cons(dirs, files), fids-cons(tree, abs-files(files), ofh), ispath(p, ROOT_INO, ino, dirs, files), p ∈ tree ⊦ abs(tree0, ROOT_INO)(dirs0), ∃ ino. ((abs|(tree, ROOT_INO, p, ino) * abs(dnode(md, sdt), ino)))(dirs)

User applied rule exists right

And obtained the following new goals

Proof step 23:
tree[p] = dnode(md, sdt), ((abs|(tree, ROOT_INO, p, ino) * ino => mkdir(# entries, md, # links(ino, dirs), m1, entries) * abs(sdt, entries)))(dirs), afs-cons(dirs, files), fids-cons(tree, abs-files(files), ofh), ispath(p, ROOT_INO, ino, dirs, files), p ∈ tree ⊦ ((abs|(tree, ROOT_INO, p, ino) * abs(dnode(md, sdt), ino)))(dirs), abs(tree0, ROOT_INO)(dirs0), ∃ ino. ((abs|(tree, ROOT_INO, p, ino) * abs(dnode(md, sdt), ino)))(dirs)

Rule argument

pos: right 2 terms: ino abort: F discard: F computed: F

Additional information

Used terms: ino