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Proof step 2 from proof file-fid (previous step)

abs(tree, ROOT_INO)(dirs), afs-cons(dirs, files), fids-cons(tree, abs-files(files), ofh), n ∈ files ⊦ ⌜n⌝ ∈ tree.fids ↔ links(n, dirs) ≠ ∅

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information