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Proof step 1 from proof files-del-eq (conclusion)

⊦ ino ∈ files0 ∧ ino ∈ files1 ∧ abs-files(files0)[⌜ino⌝ , f] ≠ abs-files(files) → (files0 -- ino = files1 -- ino ↔ (∃ af. files1 = files0[ino, af]))

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information