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Proof step 39 from proof initialization (previous step)

⌊err1⌋ ⊦ ∃ err. ⌊err⌋ ∧ ⟨err0 := err⟩ (err1 = err0)

Heuristic use patterns applied rule exists right

And obtained the following new goals

Proof step 40:
⌊err1⌋ ⊦ ⌊err1⌋ ∧ ⟨err0 := err1⟩ (err1 = err0)

Rule argument

pos: right 1 terms: err1 abort: T discard: T computed: F

Additional information

Used terms: err1