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Proof step 1 from proof path-in-eq (conclusion)

⊦ abs(tree, ino)(dirs) ∧ fids-cons(tree, abs-files(files), ofh) ∧ afs-cons(dirs, files) → (p ∈ tree ↔ ispath(p, ino, dirs, files))

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information