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Proof step 1 from proof path-in (conclusion)

⊦ ispath(p, ino, m, dirs, files) ∧ abs(tree, ino)(dirs) ∧ fids-cons(tree, abs-files(files), ofh) ∧ afs-cons(dirs, files) → p ∈ tree ∧ (tree[p].dir? ↔ m ∈ dirs)

System applied rule normalize

And obtained the following new goals

Proof step 2:
abs(tree, ino)(dirs), afs-cons(dirs, files), fids-cons(tree, abs-files(files), ofh), ispath(p, ino, m, dirs, files) ⊦ p ∈ tree ∧ (tree[p].dir? ↔ m ∈ dirs)

Proof step 1 from proof path-in (conclusion)

System applied rule normalize

And obtained the following new goals

Rule argument

Additional information