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Proof step 24 from proof refine-read (previous step)

abs-of(of)[fd] = mkfh(fid, mode, m), buf = buf0, err0 = EBADFD, n = n0, ofh = abs-of(of), root.dir?, dom of < ino, abs(root, ROOT_INO)(dirs), afs-cons(dirs, files), fids-cons(root, abs-files(files), abs-of(of)), of-cons(of, dirs, files), n0 ≤ # buf0, psynced → asynced ⊦ ⟨n0 := ?⟩ (ofh = abs-of(of) ∧ (psynced → asynced) ∧ buf0 = buf ∧ n = n0 ∧ EBADFD = err0), fd ∈ of

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

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