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Proof step 282 from proof refine-readmeta (previous step)

root[path].dir? ↔ ino2 ∈ dirs, err0 = err1, ino = ino3, ino0 = ino4, md = md0, root.dir?, dom of < ino6, abs(root, ROOT_INO)(dirs), afs-cons(dirs, files), fids-cons(root, abs-files(files), abs-of(of)), ispath(path, ROOT_INO, ino2, dirs, files), of-cons(of, dirs, files), px-parent(user, path, ROOT_INO, dirs, files), ⌊err1⌋ , psynced → asynced, ino2 ∈ dirs ∨ ino2 ∈ files ⊦ ⟨if err0 = ESUCCESS then if ino2 ∈ dirs then md := root[path].meta, ino0 := # root[path].subdirs + 2, ino := # root[path].entries else let fid = root[path].fid in md := abs-files(files)[fid].meta, ino0 := count(fid, root.fids), ino := # abs-files(files)[fid].content⟩ ((psynced → asynced) ∧ md0 = md ∧ ino4 = ino0 ∧ ino3 = ino ∧ err1 = err0)

Heuristic symbolic execution applied rule if negative right

And obtained the following new goals

Proof step 283:
root[path].dir? ↔ ino2 ∈ dirs, err0 = err1, ino = ino3, ino0 = ino4, md = md0, root.dir?, dom of < ino6, abs(root, ROOT_INO)(dirs), afs-cons(dirs, files), fids-cons(root, abs-files(files), abs-of(of)), ispath(path, ROOT_INO, ino2, dirs, files), of-cons(of, dirs, files), px-parent(user, path, ROOT_INO, dirs, files), ⌊err1⌋ , psynced → asynced, ino2 ∈ dirs ∨ ino2 ∈ files ⊦ ⟨skip⟩ ((psynced → asynced) ∧ md0 = md ∧ ino4 = ino0 ∧ ino3 = ino ∧ err1 = err0)

Rule argument

pos: right 1

Additional information

Used simplifier rules: ⊦ ⌊err⌋ → err ≠ ESUCCESS; (s)