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Proof step 55 from proof refine-readmeta (previous step)

dirs[m] = mkdir(# entries, md1, # links(m, dirs), m2, entries), err0 = ESUCCESS, root[path].dir?, root.dir?, dom of < ino6, abs(root, ROOT_INO)(dirs), afs-cons(dirs, files), fids-cons(root, abs-files(files), abs-of(of)), ispath(path, ROOT_INO, m, dirs, files), of-cons(of, dirs, files), pr(user, md1), px-parent(user, path, ROOT_INO, dirs, files), m ∈ dirs, psynced → asynced ⊦ (psynced → asynced) ∧ md1 = root[path].meta ∧ m2 + 2 = # root[path].subdirs + 2 ∧ # entries = # root[path].entries ∧ ESUCCESS = err0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 56:
dirs[m] = mkdir(# entries, md1, # links(m, dirs), m2, entries), root.dir?, root[path].dir?, dom of < ino6, abs(root, ROOT_INO)(dirs), afs-cons(dirs, files), fids-cons(root, abs-files(files), abs-of(of)), ispath(path, ROOT_INO, m, dirs, files), of-cons(of, dirs, files), pr(user, md1), px-parent(user, path, ROOT_INO, dirs, files), m ∈ dirs, psynced → asynced ⊦ md1 = root[path].meta ∧ m2 = # root[path].subdirs ∧ # entries = # root[path].entries

Rule argument

Additional information

Used simplifier rules: c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m + n = m + n0 ↔ n = n0; (s)