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Proof step 583 from proof refine-unlink (
previous step
)
⊦ abs(tree, ROOT_INO)(dirs) ∧ fids-cons(tree, abs-files(files), ofh) ∧ afs-cons(dirs, files) ∧ ino ∈ dirs ∧ dirs[ino] = mkdir(n, md, m, m0, entries) ∧ str ∈ entries ∧ ispath(p, ROOT_INO, ino, dirs, files) → entries[str] ≠ ROOT_INO
Lemma
abs-acyclic