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Proof step 1 from proof abs-dir-h (conclusion)

∀ ino. ¬ ino ∈ files ∨ ¬ ino ∈ dirs, ∀ ino. ⌜ino⌝ ∈ tree.fids → ino ∈ files, ((abs(tree, ino) * D))(dirs), ispath(p, ino, ino0, dirs, files) ⊦ tree[p].dir? ↔ ino0 ∈ dirs

System applied rule normalize

And obtained the following new goals

Proof step 2:
((abs(tree, ino) * D))(dirs), ispath(p, ino, ino0, dirs, files), ∀ ino. ⌜ino⌝ ∈ tree.fids → ino ∈ files, ∀ ino. ¬ ino ∈ files ∨ ¬ ino ∈ dirs ⊦ tree[p].dir? ↔ ino0 ∈ dirs

Proof step 1 from proof abs-dir-h (conclusion)

System applied rule normalize

And obtained the following new goals

Rule argument

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