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Proof step 10 from proof abs-dnode-emp (previous step)

((ino => mkdir(0, md, m0, m1, ∅)))(dirs) ⊦ ∃ ino1, ino0. ((ino => mkdir(0, md, ino1, ino0, ∅)))(dirs)

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: m0, m1

Additional information

Used terms: m0, m1