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Proof step 3 from proof abs-files-cong (previous step)

files0 ~ files1 ⊦ abs-files(files0) = abs-files(files1)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ files0 ~ files1 ↔ (∀ ino. (ino ∈ files0 ↔ ino ∈ files1) ∧ ( ino ∈ files0 → files0[ino].size = files1[ino].size ∧ files0[ino].meta = files1[ino].meta ∧ files0[ino].nlink = files1[ino].nlink ∧ files0[ino].content.stream to files0[ino].size = files1[ino].content.stream to files1[ino].size))
Proof step 5:
∀ ino. (ino ∈ files0 ↔ ino ∈ files1) ∧ ( ino ∈ files0 → files0[ino].size = files1[ino].size ∧ files0[ino].meta = files1[ino].meta ∧ files0[ino].nlink = files1[ino].nlink ∧ files0[ino].content.stream to files0[ino].size = files1[ino].content.stream to files1[ino].size) ⊦ abs-files(files0) = abs-files(files1)

Rule argument

spec: afs-stream name: files-iso seq: ⊦ files0 ~ files1 ↔ (∀ ino. (ino ∈ files0 ↔ ino ∈ files1) ∧ ( ino ∈ files0 → files0[ino].size = files1[ino].size ∧ files0[ino].meta = files1[ino].meta ∧ files0[ino].nlink = files1[ino].nlink ∧ files0[ino].content.stream to files0[ino].size = files1[ino].content.stream to files1[ino].size)) subst: [files1, files0] → [files1, files0] flags: <all paths>

Additional information

Used terms: files1, files0