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Proof step 11 from proof abs-has-rootpath-h (previous step)

(((ino0 => mkdir(# entries, md, m0, m1, entries) * abs(sdt, entries)) * {dirs0} ))(dirs), ino ∈ dirs, ∀ str. str ∈ sdt → (∀ ino, dirs, ino0, dirs0, files. ino ∈ dirs ∧ ((abs(sdt[str], ino0) * {dirs0} ))(dirs) → ino ∈ dirs0 ∨ (∃ p. ispath(p, ino0, ino, dirs, files))), ∃ entries0, n, n0. entries ⊆ entries0 ∧ (((ino0 => mkdir(n, md, m0, n0, entries0) * abs(sdt, entries)) * {dirs0} ))(dirs) ⊦ ino ∈ dirs0, ∃ p. ispath(p, ino0, ino, dirs, files)

User applied rule weakening

And obtained the following new goals

Rule argument

poslist: left 1

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