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Proof step 1 from proof abs-tree (conclusion)

∀ ino. ¬ ino ∈ files ∨ ¬ ino ∈ dirs, ∀ ino. ⌜ino⌝ ∈ tree0.fids → ino ∈ files, ∀ ino. ⌜ino⌝ ∈ tree1.fids → ino ∈ files, ((abs(tree0, ino) * D0))(dirs), ((abs(tree1, ino) * D1))(dirs) ⊦ tree0 = tree1

System applied rule normalize

And obtained the following new goals

Proof step 2:
((abs(tree1, ino) * D1))(dirs), ((abs(tree0, ino) * D0))(dirs), ∀ ino. ⌜ino⌝ ∈ tree1.fids → ino ∈ files, ∀ ino. ⌜ino⌝ ∈ tree0.fids → ino ∈ files, ∀ ino. ¬ ino ∈ files ∨ ¬ ino ∈ dirs ⊦ tree0 = tree1

Proof step 1 from proof abs-tree (conclusion)

System applied rule normalize

And obtained the following new goals

Rule argument

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