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Proof step 11 from proof abs-tree (previous step)

ad = mkdir(m, md, m0, m1, entries), m = # entries, ((abs(tree1, ino) * D1))(dirs), (((ino => ad * abs(sdt, entries)) * D0))(dirs), ∀ ino. ⌜ino⌝ ∈ tree1.fids → ino ∈ files, ∀ ino. ¬ ino ∈ files ∨ ¬ ino ∈ dirs, ∀ ino0. ⌜ino0⌝ ∈ sdt.fids → ino0 ∈ files ⊦ tree1.dir? ∧ md = tree1.meta

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
(((ino => mkdir(# entries, md, m0, m1, entries) * abs(sdt, entries)) * D0))(dirs), ((abs(tree1, ino) * D1))(dirs), ∀ ino0. ⌜ino0⌝ ∈ sdt.fids → ino0 ∈ files, ∀ ino. ¬ ino ∈ files ∨ ¬ ino ∈ dirs, ∀ ino. ⌜ino⌝ ∈ tree1.fids → ino ∈ files ⊦ tree1.dir? ∧ md = tree1.meta

Proof step 11 from proof abs-tree (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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