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Proof step 18 from proof abs-tree (previous step)

(((m => mkdir(# entries, md, m0, m1, entries) * abs(sdt, entries)) * D0))(dirs), D1(dirs), m ∈ files, ∀ ino. ¬ ino ∈ files ∨ ¬ ino ∈ dirs, ∀ ino0. ⌜ino0⌝ ∈ sdt.fids → ino0 ∈ files ⊦

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 4 terms: m

Additional information

Used simplifier rules: sep-ass: ⊦ (D * D0) * D1 = D * D0 * D1; from specification heap-sep[dir-heap]%sep-com: ⊦ D * D0 = D0 * D; from specification heap-sep[dir-heap]% ⊦ ((ino => ad * D))(dirs) → ino ∈ dirs; (s) Used terms: m