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Proof step 2 from proof abs-unshared-h (previous step)

n0 = n1, ((abs(tree0, ino0) * abs(tree1, ino1) * D))(dirs), ispath(p1, ino1, n1, dirs, files), ispath(p0, ino0, n0, dirs, files), n1 ∈ dirs, n0 ∈ dirs, ∀ ino. ⌜ino⌝ ∈ tree1.fids → ino ∈ files, ∀ ino. ⌜ino⌝ ∈ tree0.fids → ino ∈ files, ∀ ino. ¬ ino ∈ files ∨ ¬ ino ∈ dirs ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
((abs(tree0, ino0) * abs(tree1, ino1) * D))(dirs), ispath(p0, ino0, n1, dirs, files), ispath(p1, ino1, n1, dirs, files), n1 ∈ dirs, ∀ ino. ¬ ino ∈ files ∨ ¬ ino ∈ dirs, ∀ ino. ⌜ino⌝ ∈ tree0.fids → ino ∈ files, ∀ ino. ⌜ino⌝ ∈ tree1.fids → ino ∈ files ⊦

Proof step 2 from proof abs-unshared-h (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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