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Proof step 28 from proof abs-unshared-h (previous step)

tree0[p0] = fnode(⌜m⌝ ), ((((abs|(tree1, ino1, p1, m) * abs(tree1[p1], m)) * abs|(tree0, ino0, p0, m)) * D))(dirs), ispath(p1, ino1, m, dirs, files), ispath(p0, ino0, m, dirs, files), p1 ∈ tree1, m ∈ dirs, p0 ∈ tree0, ⌜m⌝ ∈ tree0.fids → m ∈ files, ∀ ino. ⌜ino⌝ ∈ tree1.fids → ino ∈ files, ∀ ino. ¬ ino ∈ files ∨ ¬ ino ∈ dirs ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 29:
tree0[p0] = fnode(⌜m⌝ ), ((((abs|(tree1, ino1, p1, m) * abs(tree1[p1], m)) * abs|(tree0, ino0, p0, m)) * D))(dirs), ispath(p0, ino0, m, dirs, files), ispath(p1, ino1, m, dirs, files), p0 ∈ tree0, m ∈ dirs, p1 ∈ tree1, m ∈ files, ∀ ino. ¬ ino ∈ files ∨ ¬ ino ∈ dirs, ∀ ino. ⌜ino⌝ ∈ tree1.fids → ino ∈ files ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ tree[p] = fnode(fid) ∧ p ∈ tree → fid ∈ tree.fids; (ss)