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Proof step 1 from proof absc-dnode-one (conclusion)

⊦ abs|(dnode(md, sdt), ino, str ', ino0) = _∃(λ ad. ino => ad * abs|(sdt, ad.entries, str ', ino0) ∧ ⌜ad.meta = md⌝ ∧ ⌜ad.size = # ad.entries⌝ )

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: absc-dnode seq: ⊦ p ≠ ε → abs|(dnode(md, sdt), ino, p, ino0) = _∃ (λ ad. ino => ad * abs|(sdt, ad.entries, p, ino0) ∧ ⌜ad.meta = md⌝ ∧ ⌜ad.size = # ad.entries⌝ ) subst: [ino0, p, ino, sdt, md] → [ino0, str ', ino, sdt, md] flags: <all paths>

Additional information

Used simplifier rules: and-ass: ⊦ ((D ∧ D0) ∧ D1) = (D ∧ D0 ∧ D1); from specification heap-sep[dir-heap]%and-com: ⊦ (D ∧ D0) = (D0 ∧ D); from specification heap-sep[dir-heap]% ⊦ str ' ≠ ε; (s) Used terms: ino0, str ', ino, sdt, md