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Proof step 21 from proof absc-drop (previous step)

⊦ abs|(dnode(md, sdt), ino, str ' + p, ino0) = _∃(λ ad. ino => ad * abs|(sdt, ad.entries, str ' + p, ino0) ∧ ⌜ad.meta = md⌝ ∧ ⌜ad.size = # ad.entries⌝ )

Lemma absc-dnode-rec