[Imprint][Data Privacy Statement][E-Mail]

View long theorem info. View the proof. Back to main index. View the specification. View theorem base summary, View theorem base listing, the used properties by spec, the dependency list, the symbol table,

Proof step 3 from proof entries-dom (previous step)

((abs(sdt, sdi) * D))(dirs) ⊦ str ∈ sdi ↔ str ∈ sdt

User applied rule induction

And obtained the following new goals

Proof step 4:
((abs(sdt, sdi) * D))(dirs), ∀ sdt0, sdi, D, dirs, str. # sdt0 < # sdt → ((abs(sdt0, sdi) * D))(dirs) → (str ∈ sdi ↔ str ∈ sdt0) ⊦ str ∈ sdi ↔ str ∈ sdt

Rule argument

indvar: # sdt wfpred: <

Additional information

Used simplifier rules: <; (wellfounded) Used terms: # sdt