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Proof step 3 from proof path-split-wand (previous step)

p ∈ tree ⊦ abs(tree, ino0) = _∃(λ ino1. abs(tree[p], ino1) * (abs(tree[p], ino1) -* abs(tree, ino0)))

User applied rule expand right

And obtained the following new goals

Proof step 4:
p ∈ tree ⊦ abs(tree, ino0)(dirs) ↔ (_∃(λ ino1. abs(tree[p], ino1) * (abs(tree[p], ino1) -* abs(tree, ino0))))(dirs)

Rule argument

pos: right 1

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