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Proof step 33 from proof path-split-wand (previous step)

⊦ ((D * D0))(dirs) ↔ (∃ dirs0, dirs1. dirs0 ⊥ dirs1 ∧ dirs = dirs0 ∪ dirs1 ∧ D(dirs0) ∧ D0(dirs1))

A spec-lemma