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Proof step 66 from proof path-split-wand (previous step)

((abs(tree[p], ino) * (abs(tree[p], ino) -* abs(tree, ino0))))(dirs), p ∈ tree ⊦ abs(tree, ino0)(dirs)

User applied rule apply lemma

And obtained the following new goals

Rule argument

spec: heap-sep, inst: dir-heap name: sep-mp seq: ⊦ ((D * (D -* D0)))(dirs) → D0(dirs) subst: [D, D0, dirs] → [abs(tree[p], ino), abs(tree, ino0), dirs]

Additional information

Used terms: abs(tree[p], ino), abs(tree, ino0), dirs