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Proof step 8 from proof path-split-wand (previous step)

abs(tree, ino0)(dirs) ⊦ ∃ ino. ((abs(tree, ino) * (abs(tree, ino) -* abs(tree, ino0))))(dirs)

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: ino0

Additional information

Used simplifier rules: ⊦ D(dirs) → (((D0 -* D0) * D))(dirs); (ss)%sep-ass: ⊦ (D * D0) * D1 = D * D0 * D1; from specification heap-sep[dir-heap]%sep-com: ⊦ D * D0 = D0 * D; from specification heap-sep[dir-heap] Used terms: ino0