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Proof step 11 from proof path-unfold-wand (previous step)

abs(tree[p], ino1)(dirs0), abs|(tree, ino0, p, ino1)(dirs), p ∈ tree, dirs0 ⊥ dirs ⊦ (_∃(λ ino1. abs|(tree, ino0, p, ino1) * abs(tree[p], ino1)))(dirs0 ∪ dirs)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
abs(tree[p], ino1)(dirs0), abs|(tree, ino0, p, ino1)(dirs), p ∈ tree, dirs0 ⊥ dirs ⊦ ∃ ino. ((abs|(tree, ino0, p, ino) * abs(tree[p], ino)))(dirs0 ∪ dirs)

Rule argument

Additional information

Used simplifier rules: ⊦ (_∃ nD)(dirs) ↔ (∃ ino. nD(ino)(dirs)); (s)