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Proof step 36 from proof path-unfold (previous step)

ad = mkdir(m, md, m0, m1, entries), m = # entries, (((((abs|(sdt[str], entries[str], p0, ino) * abs(sdt -- str, entries -- str)) * ino0 => ad) * abs(sdt[str][p0], ino)) * D))(dirs), str ∈ sdt, p0 ∈ sdt[str], str ∈ entries, ∀ tree, ino0, ino, D, dirs. (((abs|(tree, ino0, p0, ino) * abs(tree[p0], ino)) * D))(dirs) ∧ p0 ∈ tree → ((abs(tree, ino0) * D))(dirs) ⊦ ∃ ad0. ad0.meta = md ∧ ad0.size = # ad0.entries ∧ (((ino0 => ad0 * abs(sdt, ad0.entries)) * D))(dirs)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 37:
(( ( ((abs|(sdt[str], entries[str], p0, ino) * abs(sdt -- str, entries -- str)) * ino0 => mkdir(# entries, md, m0, m1, entries)) * abs(sdt[str][p0], ino)) * D) )(dirs), str ∈ entries, p0 ∈ sdt[str], str ∈ sdt, ∀ tree, ino0, ino, D, dirs. (((abs|(tree, ino0, p0, ino) * abs(tree[p0], ino)) * D))(dirs) ∧ p0 ∈ tree → ((abs(tree, ino0) * D))(dirs) ⊦ ∃ ad0. ad0.meta = md ∧ ad0.size = # ad0.entries ∧ (((ino0 => ad0 * abs(sdt, ad0.entries)) * D))(dirs)

Proof step 36 from proof path-unfold (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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