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Proof step 210 from proof inv-link (previous step)

dirs0[ino2] = mkdir(m2, md1, # links(ino2, dirs0), m6, entries), entries0[str] = entries1[str], dirs0[ino0] = mkdir(m0, md0, # links(ino0, dirs0), m3, entries0), files0[entries1[str]] = mkfile(m, md3, # links(entries1[str], dirs0), content), dirs0[ino1] = mkdir(m1, md2, # links(ino1, dirs0), m5, entries2), entries[str] = entries1[str], dirs0[ino3] = mkdir(m4, md, # links(ino3, dirs0), m8, entries1), dirs = dirs0[ino1, mkdir(m1 + 1, md2, # links(ino1, dirs0), m5, entries2[p.last, entries1[str]])], files = files0[entries1[str], mkfile(m, md3, # links(entries1[str], dirs0) + 1, content)], ino = inode.ino, inode = mkinode(entries[str], md3, false, # links(entries[str], dirs0), 0, m), afs-cons(dirs0, files0), ispath(parent(p), ROOT_INO, ino1, dirs0, files0), ispath(q, ROOT_INO, ino0, dirs0, files0), of-cons(of, dirs0, files0), pw(user, md2), px(user, md2), px(user, md0), px-parent(user, parent(p), ROOT_INO, dirs0, files0), px-parent(user, q, ROOT_INO, dirs0, files0), ino ∈ dirs, str ∈ entries, ino2 ∈ dirs0, ino0 ∈ dirs0, entries1[str] ∈ files0, str ∈ entries0, ino3 ∈ dirs0, str ∈ entries1, ino1 ∈ dirs0, links(ino2, dirs0) ≠ ∅ ∨ ino2 = ROOT_INO, links(ino1, dirs0) ≠ ∅ ∨ ino1 = ROOT_INO, links(ino0, dirs0) ≠ ∅ ∨ ino0 = ROOT_INO, links(ino3, dirs0) ≠ ∅ ∨ ino3 = ROOT_INO ⊦ [c_inode := getinode(mkdentry(str, entries0[str]).ino, dirs[ino, dirs[ino].meta:= inode.meta], files); err := ESUCCESS; asynced := ?] (afs-cons(dirs[ino, dirs[ino].meta:= inode.meta], files) → of-cons(of, dirs[ino, dirs[ino].meta:= inode.meta], files)), p = ε, ino ∈ files, entries1[str] ∈ dirs0, p.last ∈ entries2

Heuristic symbolic execution applied rule assign right

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ⊦ mkinode(m, md, boolvar, m0, m1, m2).ino = m; (s)% ⊦ ino ∈ dirs[ino0, ad] ↔ ino ∈ dirs; (s)% ⊦ mkdentry(str, m).dentry?; (s)% ⊦ ino ∈ files[ino0, af] ↔ ino ∈ files; (s)%⊦ ino ∈ dirs ∧ dirs[ino] = mkdir(n0, md, n, n1, entries) ∧ str ∈ entries ∧ afs-cons(dirs, files) → (entries[str] ∈ files ↔ ¬ entries[str] ∈ dirs); (ss)% ⊦ dirs[ino, ad][ino0] = (ino0 = ino ∧ ino ∈ dirs ⊃ ad;dirs[ino0]); (s)% ⊦ mkinode(m, md, boolvar, m0, m1, m2).meta = md; (s)%path-in-dirs: p ≠ ε ⊦ ispath(p, n, m, dirs, files) → n ∈ dirs; (forward) from specification afs-base