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Proof step 252 from proof inv-link (previous step)

files[entries0[str]] = mkfile(m, md, # links(entries0[str], dirs), content), dirs[ino0] = mkdir(m0, md0, # links(ino0, dirs), m3, entries0), afs-cons(dirs, files), ispath(q, ROOT_INO, ino0, dirs, files), ispath(parent(p), ROOT_INO, ino1, dirs, files), of-cons(of, dirs, files), px(user, md0), px-parent(user, q, ROOT_INO, dirs, files), px-parent(user, parent(p), ROOT_INO, dirs, files), str ∈ entries0, entries0[str] ∈ files, ino0 ∈ dirs, links(ino0, dirs) ≠ ∅ ∨ ino0 = ROOT_INO, ino1 ∈ dirs ∨ ino1 ∈ files ⊦ p = ε, entries0[str] ∈ dirs, ∃ err0. ⌊err0⌋

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 253:
dirs[ino0] = mkdir(m0, md0, # links(ino0, dirs), m3, entries0), files[entries0[str]] = mkfile(m, md, # links(entries0[str], dirs), content), afs-cons(dirs, files), ispath(parent(p), ROOT_INO, ino1, dirs, files), ispath(q, ROOT_INO, ino0, dirs, files), of-cons(of, dirs, files), px(user, md0), px-parent(user, parent(p), ROOT_INO, dirs, files), px-parent(user, q, ROOT_INO, dirs, files), ino0 ∈ dirs, entries0[str] ∈ files, str ∈ entries0, ino1 ∈ dirs ∨ ino1 ∈ files, links(ino0, dirs) ≠ ∅ ∨ ino0 = ROOT_INO ⊦ p = ε, entries0[str] ∈ dirs, ∃ err0. ⌊err0⌋

Proof step 252 from proof inv-link (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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